2x^2+4x+2ix+3=0

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Solution for 2x^2+4x+2ix+3=0 equation:


Simplifying
2x2 + 4x + 2ix + 3 = 0

Reorder the terms:
3 + 2ix + 4x + 2x2 = 0

Solving
3 + 2ix + 4x + 2x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 2ix + 4x + -3 + 2x2 = 0 + -3

Reorder the terms:
3 + -3 + 2ix + 4x + 2x2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2ix + 4x + 2x2 = 0 + -3
2ix + 4x + 2x2 = 0 + -3

Combine like terms: 0 + -3 = -3
2ix + 4x + 2x2 = -3

Add '-4x' to each side of the equation.
2ix + 4x + -4x + 2x2 = -3 + -4x

Combine like terms: 4x + -4x = 0
2ix + 0 + 2x2 = -3 + -4x
2ix + 2x2 = -3 + -4x

Add '-2x2' to each side of the equation.
2ix + 2x2 + -2x2 = -3 + -4x + -2x2

Combine like terms: 2x2 + -2x2 = 0
2ix + 0 = -3 + -4x + -2x2
2ix = -3 + -4x + -2x2

Divide each side by '2x'.
i = -1.5x-1 + -2 + -1x

Simplifying
i = -1.5x-1 + -2 + -1x

Reorder the terms:
i = -2 + -1.5x-1 + -1x

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